b^(2)-7=(6)/(b)

Solution for b^(2)-7=(6)/(b) equation:

D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

b^2-7 = 6/b // - 6/b

b^2-(6/b)-7 = 0

b^2-6*b^-1-7 = 0

1*b^2-6*b^-1-7*b^0 = 0

(1*b^3-7*b^1-6*b^0)/(b^1) = 0 // * b^2

b^1*(1*b^3-7*b^1-6*b^0) = 0

b^1

b^3-7*b-6 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6 }

1

b = 1

b^3-7*b-6 = -12

1

-1

b = -1

b^3-7*b-6 = 0

-1

b+1

b^2-b-6

b^3-7*b-6

b+1

-b^3-b^2

-b^2-7*b-6

b^2+b

-6*b-6

6*b+6

0

b^2-b-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

b = (25^(1/2)+1)/(1*2) or b = (1-25^(1/2))/(1*2)

b = 3 or b = -2

b in { -2, 3, -1} 

b in { -2, 3, -1 }